Problem Statement

 

Takahashi, Aoki and Snuke love cookies. They have A, B and C cookies, respectively. Now, they will exchange those cookies by repeating the action below:

• Each person simultaneously divides his cookies in half and gives one half to each of the other two persons.

This action will be repeated until there is a person with odd number of cookies in hand.

How many times will they repeat this action? Note that the answer may not be finite.

Constraints

 

• 1≤A,B,C≤10⁹

Input

 

Input is given from Standard Input in the following format:

A B C

Output

 

Print the number of times the action will be performed by the three people, if this number is finite. If it is infinite, print -1 instead.

Sample Input 1

 

4 12 20

Sample Output 1

 

3

Initially, Takahashi, Aoki and Snuke have 4, 12 and 20 cookies. Then,

• After the first action, they have 16, 12 and 8.
• After the second action, they have 10, 12 and 14.
• After the third action, they have 13, 12 and 11.

Now, Takahashi and Snuke have odd number of cookies, and therefore the answer is 3.

Sample Input 2

 

14 14 14

Sample Output 2

 

-1

Sample Input 3

 

454 414 444

Sample Output 3

 

1     a==b==c的时候会死循环，其他情况暴力算就行了，因为每一次操作之后最大值-最小值会减半，所以不久就能到达终止条件。

#include
     
      #define ll long longusing namespace std;int A,B,C,tot,a,b,c;int main(){	scanf("%d%d%d",&A,&B,&C);	while(!((A&1)||(B&1)||(C&1))){		if(A==B&&B==C){			puts("-1");			return 0;		}				tot++,a=(B+C)>>1,b=(A+C)>>1,c=(B+A)>>1;		A=a,B=b,C=c; 	}		printf("%d\n",tot);	return 0;}